Z score normal distribution formula:
z = (x - μ) / σ
z = (780 - 560)/125
z = 1.76
P(Z > 1.76) = 0.0392

An aptitude test is designed to measure leadership abilities of the test subjects. Suppose that the scores on the test are normally distributed with a mean of 570 and a standard deviation of 125 . The individuals who exceed 700 on this test are considered to be potential leaders. What proportion of the population are considered to be potential leaders? Round your answer to at least four decimal places.
An aptitude test is designed to measure leadership abilities of the test subjects. Suppose that the scores on the test are normally distributed with a mean of 550 and a standard deviation of 125. The individuals who exceed 700 on this test are considered to be potential leaders. What proportion of the population are considered to be potential leaders? Round your answer to at least four decimal places.
An aptitude test is designed to measure leadership abilities of the test subjects. Suppose that the scores on the test are normally distributed with a mean of 570 and a standard deviation of 125. The individuals who exceed 750 on this test are considered to be potential leaders. What proportion of the population are considered to be potential leaders? Round your answer to at least four decimal places, 5 ?
An aptitude test is designed to measure leadership abilities of the test subjects. Suppose that the scores on the test are normally distributed with a mean of 550 and a standard deviation of 120. The individuals who exceed 700 on this test are considered to be potential leaders. What proportion of the population are considered to be potential leaders? Round your answer to at least four decimal places.
An aptitude test is designed to measure leadership abilities of the test subjects suppose at the scores on tests are normally distributed with the mean of 550 and a standard deviation of 120 individuals who exceeded 750 on this test are considered to be potential leaders were proportion of the population are considered to be potential leaders run your answered to at least 4 decimal places
a psychologist has designed a questionnaire to measure individuals aggressiveness. Suppose at the scores on the questionnaire or normally distributed with the standard deviation of 90 suppose also that exactly 10% of the scores exceed 750. Find the mean of the distribution of scores care your intermediate complications to at least four decimal places. Round your answer is to at least one decimal place
A psychologist has designed a questionnaire to measure individuals' aggressiveness. Suppose that the scores on the questionnaire are normally distributed with a standard deviation of 100 . Suppose also that exactly 10% of the scores exceed 800 . Find the mean of the distribution of scores. Carry your intermediate computations to at least four decimal places. Round your answer to at least one decimal place.
A psychologist has designed a questionnaire to measure individuals' aggressiveness. Suppose that the scores on the questionnaire are normally distributed with a standard deviation of 100. Suppose also that exactly 10% of the scores exceed 750. Find the mean of the distribution of scores. Carry your intermediate computations to at least four decimal places. Round your answer to at least one decimal place. 0 X 5 ?
Scores on a standard test of mechanical aptitude are normally distributed with a mean of 72 and a s. d. of 12. If 36 subjects are randomly selected, the probability that their mean score will be at least 69 is (round to the 3rd decimal place).
Please help with BOTH of these questions!!! Thank you!!
After taking an aptitude test, the computer told Bob that he had a z-score of 1.08. If scores on the aptitude test are normally distributed, which of the following statements can Bob conclude from his score? Select all that apply. Select one or more: Bob scored within 2 standard deviations of the mean score. Bob did better than the mean score. Bob scored within 1 standard deviation of the mean score....