Solution:
Here,
Height of the wall = 1.8 meters = 1.8 x 100 = 180 cm
Width of the wall = 12 meters = 12 x 100 = 1200 cm
∴ Area of the Wall (i.e., Total Available Space) = 180 x 1200 = 216000 cm
Now, we need to maximize the total no. of boxes, so the attempt will be to fully utilize the total available space, thus, we assume that no vacant space will be left in a particular column. Moreover, there is a condition that a particular column should contain either large boxes or small boxes, not both.
Therefore,
Area of a large box column = Height of Wall x Width of Large Box
= 180 x 25
= 4500 cm
Area of a small box column = Height of Wall x Width of Small Box
= 180 x 12
= 2160 cm
Decision Variables:
Let,
x1 = # No. of Large Box Columns to be Arranged
x2 = # No. of Small Box Columns to be Arranged
Objective Function:
As an objective is to maximize the total no. of boxes, the objective function would be:
Max Z = x1 + x2
Subject to Constraints:
C1 = 4500 x1 + 2160 x2 ≤ 216000 (Total available space)
C2 = 4500 x1 ≥ 0.50 (216000) (The area allocated for the large boxes should be greater than or equal to 50% of the total space available)
∴ 4500 x1 ≥ 108000
Where, x1, x2 ≥ 0 and Integers
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please answer with full steps, thank you! Q4. A post office is planning to build mail...
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