Question

4. A student was interested in studying how cats respond to catnip. Using a sample of 15 cats, she recorded how many negative interactions (such as clawing, biting, or hissing) each cat had during a 15-minute period before begin given a teaspoon of catnip and also during the 15-minute period after getting the catnip. She wanted to test if the number of negative interactions would increase after the introduction of catnip. Cat Name # of negative interactions before catnip 0 # of negative interactions after catnip 0 Amelia Bathsheba 3 6 (a) Choose the best hypotheses test for analyzing the difference in means. (Circle one) i. two-sample t test matched pair t test iii. two-sample z test iv. matched pair z test b) Complete the hypotheses test i. Define the parameter(s) and state the hypotheses. [3pt] Boris 3 4 Frank 0 1 Jupiter 0 0 Lupine 4 5 Madonna 1 3 Michelangelo 2 1 Oregano 3 5 Phantom 5 7 ii. Posh 1 0 Find the observed sample statistic (using your calculator) and the test statistic (using a formula). Use proper notation for the sample statistic (x or P), and clearly identify your test statistic as either a Z-score or a t-score. [4pt] Sawyer 0 1 Scary 3 5 Slater 0 2 Tucker 2 2 iii. Find the p-value of your test statistic. You are required to graph the test statistic on its corresponding distribution, shade the appropriate area, and provide correct calculator documentation. Box final answer. [3pt] iv. Make a generic decision about H - [2pt] V. Make a conclusion in context. [2pt] c) Do you have any concerns about this hypotheses test? Clearly answer "Yes" or "No." Explain your answer.

Answer 1

hegahve interaction after Catnip Ginen that Sample size n-15 megadive indepathicos belme (atrin. and 12 X Y d = X-7 3 6 9 3 - 3 -) -) ។ } 6 0 - Ч. S - 3 2 4 2 3 5 5 -2 Ч 4 7 - 2 - 0 - 3 2 2 5 2 2 -1 -2 -2 ។ y O Edi = -15 Ed=35 Drze option (i) is correct. b) frei) The hypothesis is Mia M2 against Hi < M2 (one tuuled testi test statistic I ta cs Scanned with CamScanner s/n tina)

clasonate Page Where t & (di-I) - { Ed? - Edi) ² } 4 £35 - 225 1.4286 >) s² =14286 S = 1.1952 -15 - 48.6067 ta 1 1952/515 Ita 48.6067 P-value = P(A <-48.6067) me at 2-980 - 48.6 to -P-value = Are 1 so ... p-value what ever eve Chuede significance level & they must prelue is sless 27 Ho resect, is There is suffrorent evidente that evidente that the no. of negative interaction would increase after the in doduction of catnip Clima No. my CS Scanned with Scanned with CamScanner