Question

Question 4: For the Figure below determine the location of the centroid (x,y). 150 mm 150 mm 100 mm 100 mm 250 mm 85 mm

Answer 1

summary : I have divided the given entire area into two standard sections,of which centroid of their individual section area known.

2 1 F Toomm G2 . (X218) Toomm 250 mm 150 mm 150 mm 3 200 3 Q4. The given area can Radius R=85mm be divided into two Standard shape sections. section - 1 Triangle Centroid of triangular section will be (21,5) = ( 350x3, 200x) = ( 500 ) triangular Section A, - * * 250 x 200 = 25000 mu? Now Section 2: Rectangular with circular hole at the Centroid of this section will be at their geometric centre 250 + 150 b) = (400,100) Az 300 x 200 (85)2 = 37301.993 mm thus Centroid of entire section can be calculated by A, 2, + A2 X2 + 37301.993 x 400 A, + A₂ Area of itre (X2, 72 ) 100 2 Area 2 25000 x 500 3 25000 + 37301-993 ΟΥ Х 306.37 mm Now y-Corolinate of centroid A,5, + A₂ % 25000 254 + 37301.943 x 100 = 60.27 mm 25000 + 37301.993 Y A + A₂ therefore Centroid (X.7) = ( 306.37, 60.27)

Using their centroid and area, centroid of entire section can be calculated.

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