6.If sin = 0.8829, then the approximate measure of between 0° to 360° is _______
A. 62°, 28° B. 62°, 118° C. 62°, -28° D. 62°, 208°
Given that, sin(θ) = 0.8829
i.e. θ = sin-1(0.8829)
i.e. θ ≈ 62°
Now as 0° ≤ θ ≤ 360°, so we also have,
θ = (180° - 62°) = 118°
.
So option B is correct.
6.If sin = 0.8829, then the approximate measure of between 0° to 360° is _______ A....
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