
Question 31 (3 points) What is the force of gravity on you (m = 70kg) when...
What is the force of gravity on you (m = 70kg) when you are: a) On the surface of the Earth? (1 mark) b) On the International Space Station, which is 395km above the Earth's surface? (2 marks) Some constants you may need to know: - mass of the Earth: 5.98x10^24kg - radius of the Earth: 6.38x10^6m
What is the Earth's gravitational force on you when you are standing on the Earth and when you are riding in the Space Shuttle 360 km above the Earth's surface? Answer as a fraction of the surface gravity of Earth. (The Earth's radius is 6400 km.)
You sometimes hear about "zero gravity" in places like the International Space Station. Since we know Newton's Law of Gravity, we know that gravity doesn't just "stop" anywhere. What is the ratio of the gravitational force from the earth on something in the International Space Station (orbiting an average of 385 km above Earths surface) to the gravitational force from the earth on that same object when it is on the ground?
QUESTION 17 The International Space Station which presently has mass of about 420,000 kilograms, maintains an orbit with an altitude of between 330 and 435 kilometers (205 and 270 miles respectively) above the Earth surface by means of re-boost maneuvers using the engines of the Zvezda module or visiting spacecraft to compensate for 2 km/month orbital decay due to the atmospheric drag. Calculate the following for the low orbit of the ISS (330 kilometers above the Earth surface), assuming that...
The International Space Station whose mass is 420 tons is orbiting at an altitude of about 400 km above the earth's surface. The mass of the earth is 5.976 × 102 4 kg and the radius of the earth is 6.378 × 106 m. (a) What is the gravitational force exerted on the Space Station by the earth? (b) Assuming a circular orbit, what is the period of the International Space Station's orbit? (c) Assuming a circular orbit, what is...
Does the force of gravity
alone provide the means for the centripetal force, is this why they
are equal ? For explaining why there is no normal force, could you
see it as the astronaut having the same acceleration as the ship
and so the relative acceleration = 0, so it's under the illusion
almost of having no acceleration so there's no force ? Please !! If
you have different reasoning please share. I'm just trying to wrap
my head...
1 to 6-3 Law of Universal Gravitation (I) Calculate the force of Earth's gravity on a spacecraft 2.00 Earth radii above the Earth's surface if its mass is 1480 kg.
Calculate the force of gravity on the 1-kg mass if it were 1.3×107 m above Earth's surface (that is, if it were three Earth radii from Earth's center). Express your answer to two significant figures and include the appropriate units.
A. A crate of mass 66.8 kg rests on a level surface, with a coefficient of kinetic friction 1.49. You push on the crate with an applied force of 1,178. What is the magnitude of the crate's acceleration as it slides? Part A answer: 3.0327 m/s^2 B. Take the same crate of mass 66.8 kg and the same coefficient of kinetic friction 1.49, but now place the crate on an inclined surface, slanted at some angle above the horizontal. Now...
You have a rocket of mass 2350 kg. How much work does the force of gravity do on the rocket if it moves from Earth's surface to 3.0 times the Earth's radius away? Be careful to use the definition of work that accounts for a force that changes based on location! J G = 6.67 x 10-11 m3/kg/s2 MEarth = 5.97 x 1024 kg REarth = 6.37 x 106 m What is the change in gravitational potential energy as the...