

samplex Problem1: Solve the following problem using simplex method: Max. z = 2 x1 + x2...
Use the dual simplex method to solve the following LP. Max z = -4xı - 6x2 - 18x3 Subject to 2x1 + 3x3 2 3 3x2 + 2x3 25 X1, X2, X3 20
Use the dual simplex method to solve the following LP. Max z = -4xı - 6x2 - 18x3 Subject to 2x1 + 3x3 2 3 3x2 + 2x3 25 X1, X2, X3 20
Use the dual simplex method to solve the following LP. Max z = -4xı - 6x2 - 18x3 Subject to 2x1 + 3x3 2 3 3x2 + 2x3 25 X1, X2, X3 20
Problem 3. Solve the following LP by the simplex method. max -x1 + x2 + 2xz s. t x1 + 2x2 – x3 = 20 -2x1 + 4x2 + 2x3 = 60 2xy + 3x2 + x3 = 50 X1, X2, X3 > 0 You can start from any extreme point (or BFS) that you like. Indicate the initial extreme point (or BFS) at which you start in the beginning of your answer. (30 points)
Use the simplex method to solve this problem
Objective Function (OF)
Max Z = 5x1 + 3x2 + x3
Restrictions
x1 + x2 +
x36
5x1 + 3x2 + 6x315
Xi0
Q3. (Dual Simplex Method) (2 marks) Use the dual Simplex method to solve the following LP model: max z= 2x1 +4x2 +9x3 x1 x2 x3 S 1 -x1+ X2 +2x3 S -4 x2+ X1,X2,X3 S 0
Q3. (Dual Simplex Method) (2 marks) Use the dual Simplex method to solve the following LP model: max z= 2x1 +4x2 +9x3 x1 x2 x3 S 1 -x1+ X2 +2x3 S -4 x2+ X1,X2,X3 S 0
2. Consider the following LP: Min z = -4x1 - 5x2 + 3x3 Subject to X1 + x2 + x3 = 10 X1 X2 > 1 X1 + 3x2 + x3 = 20 X1, X2, X3 20 (a) Solve the problem by Big M method. (b) Solve the problem by two-phase method.
Using the dual simplex, please solve the following linear program min z = x1 +x2 s.t. 2x tx2 5 2x1 + 3x2 26 (all x's are nonnegative)
Using the dual simplex, please solve the following linear program min z = x1 +x2 s.t. 2x tx2 5 2x1 + 3x2 26 (all x's are nonnegative)
Solve the linear program using
the simplex algorithm method
maximize Z = 5x1 + x2 + 3x3 + 4x4 subject to: x1 – 2 x2 + 4 x3 + 3x4 s 20 –4x1 + 6 x2 + 5 X3 – 4x4 = 40 2x1 – 3 x2 + 3 x3 + 8x4 5 50 X1, X2, X3 , X4 20
QUESTION) Solve the DP given below using the revised simplex method. Min Z = X1 + 2x2 + 4x3 Öyle ki; 2x1 – 2x2 + x3 = 0 -2x1 + 4x2 + x3 = 8 4x1 + 3x2 – 2x3 = 17 X1, X2, X3 20