Question

2- The ABEF bent tube is supported by the AH cable and supported by bearings C and D.

a) Knowing that the AB portion in 250mm in length determine the value of the tensile force in the AH cable.

b) Express the result of the force in AH in Cartesian form.

N H А B С 30° 250 mm! D E Х 300 mm 250 mm 50 mm E Y 50 mm 400 N

Answer 1

solution : 250 mm Cy B 30 D E Y 300 mm 12.50 m F 400N 50 AB= 250 mm coordinates of required points are, B(0,0,0) C (0,50,0) , D(0,350,0) E (0,400,0) ;F ( 250,400,0) W(0,0,250 ) 7 For Coordinate of point A. Ax = A B Cos 30° 250 COS 30° 216.50 mm Az = A B sin 30° = 250 sin 30 = 125 A (216.50, 0,125) Now, Force, vector TAH is given by (+216.50 î. - 216.50 L + 125 K TAM TAH AH AH TAH | J216.50² + 125² A TA -0.866 Tat i + oos TAU ☆ AH

Now, Taking moment about y anis we get, & My 400(250) - (0.866 TAH) (125) - 0.5 TAH ( 216.50) = 0 - => 216.5 TAH 10,0000 TAH 461.89 N. Hence, In Cartesian form. Ta 361-02 1 + 230.94 K AH Aus Aus