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Question 21 1 pts Results from a 2 Factor ANOVA produced the following FA(2, 48) = 2.25, p >.05, FB(1, 48) = 12.07, p<.05 and
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Answer #1

Solution

From given formation

n for each cell is 9

Explnation:

Since for number of factor A = 3

number of factor B = 2

And interaction A*B = 3*2 = 6

Error degrres of freedom = 48

So total number of units = 54

divide into 6 equal parts so 54/6 = 9

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