Question

Laboratory activities: Figure 1 shows the drawing and specifications of a simple workpiece with two features of size (the small hole and the larger one) on it. This workpiece is to be produced in large quantities in the FAME area. 3101.003 .00B А в с 4371.002 0.008 А в с q 900.008 1.400.000 8 030 800 2.002 .030 Figure 1

Answer 1

Detailed answer of above asked question is solved as below.

Given Small Hole diameter 00.310 + 0.003 position x 4y= 0.4+0.008 large Hole drameter 00.487 & 0.002 Position х = 0.9 +0.008 0.6 + 0.008 y → Workpiece # 1 (for table 2) > Small hole drameler, limit Ilal = 0.810-0003 : 0.001 FULL = 0.310 +0.003= 0.313 0.310 measured diameter of small hole of WP1 is which is coithin the permitted limit of tolerance, so that small hole diameter of tip 1 is accepted. 2) Small hole position 0.4 to 008 = 0.408 limit x dy direction for ALCU - 04-0'008= 0.392 Measured position of small hole of WPi is x = 0.4064 position by both the coordinate is within the Y = 0.402. permitted limit of tolerance, so that small hole position tol. Is Accepted 3) large hole drameter = limit o. 437 4 0.002 = 0439 bony ell. 0.467 0.002 = 0.435 measured diameter of lange hole of Wp q is. 0.459., which is within the permitted limit of tolerance, so that large hole drameter is Accepted 4) large hole position limit inx-direction ? 0.9 + 0.00% 0.908 0.9 -0.008 = 0.892 Measured position in x-direction is 0.895 which is within the limit → UCL = 0.6 t 0.008 0.608 in yo direction LCL = 0.6 -0.008 = 0.592 Measured position in ydirection is 0.604 which is within limit, le both the coordinate of position are within limit so that large hole position' tol, is accepted UCL LEL

All above results in table 2. calculated value Decision 0.310 constraint Small Hole biameter. Small Hole position Tol large Hole Drameler. large Hole position Tol- Workpiece # Permissible value 0.310+ 0.003 xdy 04 to 008 0.484 1 0.002 Х O'90.008 Y 0.6 t 0.008 A A Y = 0.406 y = 0.402 0.439 X = 0.895 Y = 0.604 A Conclude that work plece I (WPI) is within the limit by diametert position so that workpiece f is 'Accepted!