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2XY(g) + Z2(g) → 2XYZ(g) Calculate AGº of this reaction at 298K. Substance: XY(8) Z2(8) XYZ(3)...
2XY(g) + Z2(g) → 2XYZ(8) Calculate AGº of this reaction at 298K. Substance: XY(g) Z2(g) XYZ(3) AH°F (kJ/mol): 78 0 87 S°(J/K.mol): 340 243 651
AH-116.4 kJ/mol 4. Consider the following reaction: NH.NO, (s) N20 (8) + 2 H20 (g) Calculate AGⓇ for the reaction. Substance S” (J/mol K) NH.NO, (3) 151 N:0 (8) 220 H:0 (9) 183 5. The first step in the commercial production of titanium metal is the reaction of Tio: with chlorine an graphite: TiO2 (s) + 2 Cl: (g) + 2C (5) Tici: (1) + 2 CO(g) Calculate AGº for the reaction. Substance AG? (kJ/mol Substance AG® (kJ/mol) C(s) TiCl...
QUESTION Use the given data at 298 K to calculate AGº for the reaction 2012(g) + SO2(g) → SOC12(g) + Cl20(g) Substance: Cl2 (8) SO2(8) SOCI2(g) Cl20(g) AHºf (kJ/mol): 0 -296.8 -212.5 80.3 Sº (J/mol-K): 223.0 248.1 309.77 266.1 O 129.3 kJ 133.6 k) 196.0 k) 199.8 k) 229.6 kJ
Consider the reaction: 2HBR(g) >H2(g) + Br2() Using standard thermodynamic data at 298K, calculate the free energy change when 1.51 moles of HBr(g) react at standard conditions AG° kJ rxn AHof (kJ/mol) AG°F (kJ/mol) s° (J/mol K) Beryllium Вe(s) 0 9.5 -569.0 ВeO(s) -599.0 14.0 Be(ОН)2(s) -902.5 -815.0 51.9 AH°f (kJ/mol) AG°f (kJ/mol) s° (J/mol K) Bromine Br(g) 111.9 175.0 82.4 Br2() 152.2 0 0 Br2(g) 30.9 3.1 245.5 Br2(aq) -3.0 4.0 130.0 -121.0 -175.0 82.0 Br (aq) BrF3(g) -255.6...
AH = -116.4 kJ/mol 4. Consider the following reaction: NH4NO3 (8) N20 (g) + 2 H20 (g) Calculate AGº for the reaction. Substance Sº (J/mol K) NH4NO3 (s) 151 N20 (8) 220 H2O (9) 183
Elemental boron can be formed by reaction of boron trichloride with hydrogen. BC13(g) + 1.5H2(g) → B(s) + 3HCl(g) Calculate AGº for the reaction at 500K. Substance BC13(g) H2(g) B(s) HCl(g) AH°F (kJ/mol): -403.8 -92.307 AG°f (kJ/mol): -388.7 o 0 -95.299 S°(J/K·mol): 290.1 130.7 5.86 186.9 AG° = -RTINK AG = RTinQ + AG° AG° = AH° - TAS° -78.6 kJ 293.4 kJ 78.6 kJ 86.7 kJ -86.7 kJ
AG°= AH-TAS AG=AGº+RTinQ where R=8.314 J/mol K 1. Calculate AGº for the following reaction at 25 °C if AH°= -1854 kJ/mol; AS°= -236 J/mol K CH-COCH3(g) + 402(g) → 3C02(g) + 3H2O(1) 2. NH.NO, dissolving in water is a spontaneous process. As it dissolves, the temperature of the solution decreases. Based on this, what must the signs (positive or negative) of AG, AH, and AS be?
AH = -116.4 kJ/mol 4. Consider the following reaction: NH4NO3 (s) N20 (g) + 2 H2O (g) Calculate AGº for the reaction. Substance Sº (J/mol K) NH4NO3 (s) 151 N20 (g) 220 H2O (g) 183
Substance H2O (1) HF (8) AS° (J/mol x K) 70.0 173.8 291.5 AH° (kJ/mol) -285.8 -273.3 -1220.5 -395.7 SF. (g) SO; (g) 256.8 (19) Using the table above Determine AS, Hº, and AGº for the following reaction: SF6(g) + 3H2O(0) + 6HF(g) + SO3(g)
In which reactions is the AS rxn positive CIO(g) + O2(g) - CI(g) + 2O2(8) RXN 01 203(g) 302(8) RXN 02 2 NO2(8) N204(8) RXN 03 RXN 02 only RXN 01 and RXN 02 RXN 01 only All three of the reactions None of the reactions RXN03 only RXN 02 and RXN 03 ORXN 01 and RXN03 - You have a process that is: Endothermic, Entropy decreases. Choose the best answer: O always non-spontaneous O spontaneous at high temperatures O...