Electric field, E = (u0 N R^2/2 L r) dI/dt
E = [(4 pi x 10^-7 x 10^5 x 0.2^2)/(2 x 5 x 0.8)] x 1000
Electric field, E = 0.628 V/m
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2. A long, straight solenoid is 5,00 m long, has 10 turns, and a radius of...
2. A long, straight solenoid is 5.00 m long, has 105 turns, and a radius of 20.0 cm. The current in the windings is increasing at a rate of 1000 A/s. Find the magnitude of the induced electric field (in V/m) near the center of the solenoid (2.5 m from each end) and 80.0 cm from the axis. (A) 0.108 (B) 0.400 (C) 0.628 (D) 1.13 (E) 1.59 (F) 2.00 OA OB OC D 0 ОЕ OF
A long, thin solenoid has 450 turns per meter and a radius of 1.04 cm . The current in the solenoid is increasing at a uniform rate didt. The magnitude of the induced electric field at a point which is near the center of the solenoid and a distance of 3.55 cm from its axis is 8.00×10?6 V/m . a)Calculate didt.
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3. Find the magnitude of the induced electric field outside a long solenoid at a distance rZR from its central axis if the solenoid is of radius R and hasn turns of wire per unit length and carries a time-varying current that varies sinusoidally as l = 1-cos cot where I-is maximum current and ω is the angular frequency of the current source. 4. A rectangular coil of N windings had an emf of 40 mV induced in it wher...
Along, thin solenoid has 440 turns per meter and a radius of 1.17 cm. The current in the solenoid is increasing at a uniform rate is 7.60x10-6 V/m. di The magnitude of the induced electric field at a point which is near the center of the solenoid and a distance of 3.44 cm from its axis You may want to review (Page) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Induced electric...
A 10.5-cm-long solenoid with radius 2.85 cm is closely wound with 325 turns of wire. The current in the windings is 8.90 A. Compute the magnetic field at a point near the center of the solenoid. T
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