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A string vibrates according to the equation:

y= (0.5 cm) ( sin ( 5 cm”) x ] cos(407 secº)

a) What is the amplitude of the and velocity of the component waves whose superposition can give rise to this vibration?

b) What is the distance between nodes?

c) If this standing wave has 3 antinodes, what is the length of the string?

PLEASE INCLUDE WRITTEN EXPLANATION

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Answer #1

y = (0-50m) (Sir (m)»J.cos( 409 secº) let component Waves are y, Asin(kx + Wt) and ya A sin (kr Cut) A sin(kx-wt) Ya Ined y &Amplitude of component Waves IA 0.25 Ah IA 0.25cm 40 T Sect 7 sont velocity of componen Waves 4 off seet 7 k cm v 120 ml = 1.Distance between nodes 6 см - 3cm 3 Andinodes Andinode Andind de Andi-node li 31/2 length of string 31 3 yoch Ich l gom

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