Question

need help really bad! dont understand

0 Consider the following set of ungrouped Sample data. Answer parts Athrough 4 4 4 4 0 2 1 5 6 10 (A) Find the mean and standard deviation of the grouped sample data x=cType an integer or a decimal) (Type an integer or decimal rounded to three decimal places as needed (B) What proportion of the measurement lies within 1 standard deviation of the mean Win 2 standard deviations? Wandard deviations? Ils of the data values tal within 1 standard deviation of the mean of the data westal within 2 standard deviations of the man In the data values tall within 3 standard deviations of the mean Based on your answers to pan () Would you conjecture that the histogram is approximately be shaped Explan O A Yes, because most of the data valus all near the man with few dana vas her from the man OB Yes, because about the same number of data vaalea the means hoe and the man ON because most of the data oltarther than andard deviations from the man 2 GO O Type here to search 2 F9 P $ @ 8 7 % 5 # 3 8 4 6 R. Т. Y E W Q Tab K

Answer 1

Date Page Sol". Given numbers arers 4, 4, 4, 4,0,?,1,5,6,7. => N=10 = no. of terms. A. = Mean Sum of all numbers total numbesi of numbers X 4+4+4+4+0+.2+ 1 +5+6+7. 3:7 Now, sample 6:$ = standard deviation = (4-3.7) 7 (4-3,7)? +(4-3:7)2+(4-337)}-(0-3.73 10 +(2-3•7)+(1-3,7)+(5.-3.756-31757-3.7) 1 2 (0:-M)2 V (N- S = 4211/9 14065 Y16777- S 2,1628 AY (В. Measurements lying withiin 1 of areas tetiven Es between 317-21162 ) 3.3 +2116. Measurements between SiR & 5.9 => 10% by Measurements lying within 2 std den are in between 317 39 2(2116)=) between -0168 88.08 100% Hence, t/w 317 + 3(2:16) ů also 100 % Al ①. A yes, because (hall) most of the )) o mean : CS Scanned with CamScanner

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