Question

Chapter 18, Problem 016 When the temperature of a metal cylinder is raised from 0.0°C to 47.8°C, its length increases by 0.11%. (a) Find the percent change in density. (b) What is the metal? Use Table below. Some Coefficients of Linear Expansion Substance a (10) loe (at O'C) 51 Lead 29 Aluminum 23 Brass 19 Copper 17 Concrete 12 Steel Glass (ordinary) 9 Glass (Pyrex) 3.2 Diamond 1.2 Invar 0.7 Fused quartz 0.5 Room temperature values except for the listing for ice "This alloy was designed to have a low coff cient of expansion. The word is a shortened form of invariable."

Answer 1

BT= change in temperatime = (17.8-9'c = 47.8°C if to = original length original area. then, o(1+267) - DL= LOKAT L = LAT LEL AL given, st kl KID = oll - att 0-11 if a = thermal coefficient of wear expansion then y= thermal wefficient of volumetric expansion = 30 AV = VYOT 4V VA = 36 AT = w sv%= (3x0.11% density = f = mass volume öße min) = -) (%) -(Y) (ov) change in density density = 0.33% (decret) b) set film #me I'c = 23.0/x106/2 23X10/2 = Aluminium COOT