Fx is X component of hydrostatic force which is calculated using the projected area of quarter circle and acts at a depth Xp from free surface shucks Fy is y component of hydrostatic force which acts Yp apart from the hinge itself.
![4р - 14 +1 = F = 38 Ap, X: 480 x [06x3]x (- 3 fx = 5.2974 KN 0.4313 +.3 2044 м AR 12.6х3x. 3 fu= weight of liquid coloumn abo](http://img.homeworklib.com/questions/ed0f54f0-f2f5-11ea-91ed-475d5bae0619.png?x-oss-process=image/resize,w_560)

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A water trough of semicircular cross section of radius 0.6 m consists of two symmetric parts...
please help...add sketch
1. A water trough of semicircular cross section of radius 0.6 m consists of two symmetric parts hinged to each other at the bottom, as shown in Fig. 1. The two parts are held together by a cable and turnbuckle placed every 3 m along the length of the trough. Calculate the tension in each cable when the trough is filled to the rim. Draw a sketch to illustrate the problem solution and show all your work...
(1 point) Cable Hinge A semicircular trough with a diamter of A 2.2 m is filled with pure water with a density of 1000kg/m3. Two symetric parts are hinged together at the bottom edge and connected with a cable on the top edge. Assume that the width of the tank is 읊 into the page. Calculate the tension in the cable. Fr= 17386