Question

Two prisms with the same angle but different indices of refraction are put together Due this Friday, Jul 31 at 11:59 pm (EDT) Incident ray ni 5.0 cm n12 -20.0 cm Figure 22.38 Problem 22.16. (c22p16) Two prisms with the same angle but different indices of refraction are put together to form a parallel sided block of glass (see the figure). The index of the first prism is n = 1.54 and that of the second prism is n2 = 1.76. A laser beam is normally incident on the first prism. What angle will the emerging beam make with the incident beam? (Compute to the nearest 0.1deg) Submit Answer Incorrect. Tries 3/5 Previous Tries

Answer 1

Dear Student,

Final answer is 3.1 degree.

Details solution is as follows...

Happy to help you.

Incident ray tand, = 2 = 14 Q = tant + = 14.0362° n-n, = 1.54 froom snell's law 5cm n, sing, n, sino, n=n2 =1176 20 cm. Sino₂ = n, sinal OW n=1 82 O2 1 sint (miscamos) - sint 11.54xsin (14.036) 1.76 12.2524 ° here deviation (81= 1.7838 (07-03 Now from the figure, O3 = 8 =1.78 38° In point a. Mersin O3 = 1 x Sinu sint (M₂ Sinon) = 3.14050 : 2nd deviation 82-04-03) - (311405 - 1 → 82 = 1.3567 *13567 : Total deviation &=&etdz = (1.7838+1.3567 67) = 3.14050 23.10 Imorging beam makes an angle with incident beam 4 1.7838) = 3.1