Question

?　?????????　??　??　???　?????　?????．　ａｎｄ　??　???????　??　??　????????　??　２．１０　??　????　???　???????　??　???　?????　??　??　???????　??　????????　?????．　???　????　???????????　????　???　?????????　????????　??????　?　２４－????　??????？　　（??????＝５.９８?１０２４　??，　??????＝６.３７?１０６　?）

Answer 1

First we calculate the velocity of the satalite in the orbit. Then we find the time period of the revolution. Now we can calculate no of revolutions.

Salt fg = to gv Mera wuz को Relh im Retur G Me (Reth) halokm 6.674 & 5.98810 +24 (6370+ 210)x103 v= 7785.75 mis TE PT (Reth) = v 248 360o 140 of revolutions na t T na 24x360o 25/65800103 7785.75 - 24x3600x7785. 75 3 (6 CKD XI) n = 16.27 revolutions na 16 Ans Scanned By SelfScan