Question

Question Help The accompanying data represent the total travel tax (in dollars) for a 3-day business trip in 8 randomly selected cities. A normal probability plot suggests the data could come from a population that is normally distributed A baxplot indicates there are no outliers. Complete parts (a) through (c) below. 69.59 79.03 69.36 82 32 82 68 87.39 101.74 97 97 (a) Determine a point estimate for the population mean travel tax A point estimate for the population mean travel tax is 5 83.76 (Round to two decimal places as needed) (b) Construct and interpret a 99% confidence interval for the mean tax paid for a three-day business trip. Select the correct choice below and fill in the answer boxes to complete your choice. (Round to two decimal places as needed) A. One can be 99% confident that the mean travel tax for all cities is between $83.76 and 666 O B. The travel tax is between Sandsfor % of all cities OC. There is a % probability that the mean travel tax for all cities is between $and $ OD. One can be % confident that all cities have a travel tax between and $ (c) What would you recommend to a researcher who wants to increase the precision of the interval, but does not have access to additional data? The researcher could decrease the level of confidence Click to select your answers) de 4:46 PM 7/30/2020 Type here to search

Answer 1

The solution to this problem is given by

Standard deviation (Sx). solution - (x-x)2 Х 200.788 69.59 22:372 79.03 204.36 69.36 2.0736 8232 1.1664 88.68 13.1769 87.39 101.74 323.2804 201.9241 97.97 {(x-xja EX = 670.08 = 972.143 670'08 = 83.76 Y = Ex= 8 {(x-X2 n- = √138.877 972.143 8-1 s-d. (3x) = 11.7846

$ © The toint estimade for tobulation mean travel tam is 83.176 In The 99% C for ill is given by (taiga tooos (7) = 3,499 $ 3.76€ (3.499 111.7846 at taja in S 83.76 * 14.578 (83.76 – 14.578, 83.76+14.578) ( 69.182, 98-338) E 169.18, 98.34) (A l One Can be 199% confident that the travel fare for all cities is between $ 169.18 and mean 98.34 decrease the (CI The researches could level of confidence