Question

please answer and show all steps

(3) Using the Law of Sines, solve the non-right triangle where B=5°, A= 10°, c=5 (4) Using the Law of Sines, solve the non-right triangle where b=2, c=3, B = 40° I

Answer 1

To find Sice a can use a Sinio Sinics OLYO. 2598 So.1136 - SXO.1736 02588 0.868 02588 a-B35394 NO We can find Side b the equations S Sin 165 (from 0.256€ bro 2188 = $700577

b - 570.0871 0.25 88 b-0.4355 0.2588 b = 1.6827 b = 1.683 Hence -angle (= 165 b2 1683 and a = 3.353 Answer Lc=165° a3.353 b~ 1.683 Hence it ý solved. 4 Sol: Given b=2 C = 3 B: 40 c 6 = 3 a 410 ?

Can find Lc wing Sine law b SinB Sinc 3 Sinuo Sinc 23 Sinc 0 6428 2x Sinc = 3x0.6428 Sinc-370 6428 2 Sinc-1.9284 2 Sinc-0.9642 C=Sio-1 (6.9642) - 74.6°

LA2+ 145.4°= 180° LA2 = 180-145.40 CA2 = 34.60 آبان ۸ We Can find law of using Sine Az b Sin B SinA A 2 - 2 Sin 34.6 Sinuo a 2 2 - 0.5678 0 6428 a 2x0.642 8 = 2x0.5678 los a 2 = 2x6.5678 0.6428 62 a 2 = 1.1356 34.6 06428 a 2-1 17

Hence the unknown values are LAI = 65.40 Loi-74.60 a.~ 2.83 LA2 - 34.60 LC2 = 105.4 A 2 ~ 1.77