Question

A concave spherical mirror with a radius of curvature of 100 cm generates an inverted image at a distance of 2.5 m from the mirror. What is the magnification of the image? 1.5 -4.0 0 -5.0 -0.25 O 0.25

Answer 1

Radius of curvature of the concave spherical mirror = R = 100 cm = 1 m

Focal length of the concave spherical mirror = f

f = R/2

f = 1/2 m

f = 0.5 m

Distance of the object from the mirror = d_o

The image formed is inverted therefore the image formed is real and in front of the mirror.

Distance of the image from the mirror = d_i = 2.5 m

$\frac{1}{f} = \frac{1}{d_{o}} + \frac{1}{d_{i}}$

$\frac{1}{0.5} = \frac{1}{d_{o}} + \frac{1}{2.5}$

d_o = 0.625 m

Magnification of the image = M

$M = -\frac{d_{i}}{d_{o}}$

$M = -\frac{2.5}{0.625}$

M = -4

Magnification of the image = -4