Answer:
a)
Given,
Range = xbar +/- 3*(Rbar/d2)
substitute values
= 0.8267 +/- 3*0.11/1.693
= 0.8267 +/- 0.1949
= (0.6318 , 1.0216)
b)
Maximum weight = 1.0216
c)
No
Minimum weight = 0.6318
d)
Consider,
Rbar/d2 = 0.11/1.693 = 0.06497
Consider,
P(X < 0.75) = P(z < (0.75 - 0.8267)/0.06497)
= P(z < - 1.18)
= 0.1190001 [since from z table]
= 0.1190
= 11.90%
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