Question

consider the rectilinear shape below. Find the perimeter and the area of the figure.

18 in 4 in 6 in 7 in 6 in 4 in

Answer 1

А 18 in uén (AB=Lain с L D 6 in K Finl from symmetry 7 AB=LC =IF=HO F=HG) = 18 éve (AL AL= BC = HI = FG FG) = 4 in (JK = DE = 7 in) KL = CD= EF= IJ - 6 en J E bin I F 4 in (k L = c.in H AB=LC = 18 LC= KL +Dk+CD 18 = 6 + DK + 6 + 18 = 12 +Dk by Symmetry DK= 18-12= 6in : DK=JE = 6 in # Perimeter = AB+BC+CD+DE+EF+FG + HG+HI +I J Jk+KL+AL = (18+4+6+7+6+4+18+4+6+7+6+4) =(18+18)+(4+4+4+4) +(6+6+6+6)+(7+7) = 36 + 16 +24+ 14 Perimeter = go in rectangle # Area required =(Area of. "ÄB OL) +(Area of IFGH) +(Area of rectangle KDEJ) {use use area of rectangle = length * Width} required Area CAB*BC) + ( HG *F9)+(JE *DE) = ( 18 * 4)+(18+4) + (6*7) = 72+72 +42 in ² required Area = 186 in Perimeter = 90 in Area = 186 in? Answer