Question

The beam in Fig. P-698 is supported at the left end by a spring with a On the beam, $E=10\times 10^{9}N/m$ and $I=60\times 10^{6}mm^{4}$ . Compute the deflection on the end of the beam.

Ans. $\delta =13.6mm$

Answer 1

Sol" Let F be the force where reaction spring is in contact with beam -L w 7 mm 1 As, deflection of both the beam has to spring and end of be some So, Sspring Send of been = ) F k ( deflection due to selfweishd deflection due to F. WLt EL FĽ ki 3 ELO 8 E1 #L 3 14 به -> F + JEJ ( ¢ Floor tot 3 t 8 E1 04 3% (10x108) (60*1062 1012) 60x103 800 R 4 44 80 (108108) (602206) +7012 FE 2477.42N 817:02/N soi deflection sa SE E = k 2477842 60x103 87. 021 for 103 8=13.61 mm Ans