Since only c has the correct P, so we have no need to find D,
but for proper understanding, there is the solution of D also.
THANK YOU!
![Now, & 1 So, A: PDPT =) PlA = P1 PDP =DP PIAP a Dptp = D =) D=PHAP pta adj AP (adjp) PPT =/ D = papa ${-4}] [11] 7 72-4 -4](http://img.homeworklib.com/questions/20052e70-f462-11ea-a210-e7870a4d5944.png?x-oss-process=image/resize,w_560)
Diagonalize
a.
b.
c.
d.
e.
f.
Diagonalize A A = 1 3 4 2 a. A = PDP-1 b. A = PDP-1 1 Р 1 1 OC. A = PDP-1 -1 3 P = 2 5 d. A = PDP-1 -3 1 P= -4 1 e. A = PDP-1 1 -1 P 3 1 Of A = PDP-1 P-[31] -- [6-2] [37] - [64] P=[ +3 z] --[: = D = 10 03
Orthogonally diagonalize as
a.
b.
c.
d.
e.
f.
Orthogonally diagonalize A as PDPT A = ['$ ] a. 1 2 P = 1 2 1 2 D [ 6 0 0-4 1 2 b . Р = 1 1 2 12 1 1 2 2 D = 16] -60 04 - C. 2 2 P= D = 0-4 6 0 2 12 *-=[17] --66--] 0-60] O e. 1 2 v2 P = 2 12 O f. 1 2 Sila...
1 1 3 3 5. Diagonalize the matrix A = -3 -5 -3 if possible. That is, find an invertible matrix P and 3 3 a diagonal matrix D such that A = PDP-1 6. If u is an eigenvector of an invertible matrix A corresponding to , show that is also an eigenvector of A-!. What is the corresponding eigenvalue?
/ 4 100 (12 pts.) Let A=| 0 -1 0). If it is possible to diagonalize A, find P and D such that A = PDP-1. 0 0 4 If it is not possible to diagonalize A, explain why not.
linear algebra 2 part mcq
part a
part b
r(A) Find and n(A) A = 1 - 3 4 -1 9 -2 6 -6 -1 -10 -39 -6 -6 -3 3 -94 9 0 a. r(A) = 5 n(A) = 0 b. r(A) = 3 n(A) = 2 c. (A) = 0 n(A) = 5 d. r(A) = 1 n(A) = 4 e. r(A) = 4 n(A) = 1 f. r(A) = 2 n(A) = 3 А Diagonalize A =...
(31 20 3 3 5. Diagonalize the matrix A = -3-5-3 3 3 a diagonal matrix D such that A = PDP-1. if possible. That is, find an invertible matrix P and
1. The matrix A is factored in the form PDP-1. USe the Diagonalization Theorem to find the eigenvalues of A and a basis for each eigenspace. 54 0 -2] -20 11 5 007 0 0 1 25 4 0 1 2 0 5 0 2 1 42 0 0 5 0 0 0 0 4 - 1 0 - 2 2. Diagonalize, if possible, the matrix A below, given that the eigenvalues are 1 = 2, 1. If not possible,...
Orthogonally diagonalize A as PDPT A = O a. 1 V2 2 P= 0-102 2 2 b. 12 P = o=[6] -4 0 06 √ √2 OC. 2 V2 -60 P= D = 0 4 2 V2 002-[17] -[8] D- [8 ] Oe. P = 2 V2 Of. 2 2 P= p=[6 -] 1 1 2 2
Orthogonally diagonalize A as PDPT A = [5] O a. 1 P = 1 v2 V2 1 1 /2 √2 D = -[6-4) b. O 1 2 1 2 6 0 P= D = 1 1 0-4 2 2 1 2 12 P = D = = [ ] 0-4 6 0 1 v2 d. 1 1 12 P = 12 1 v2 0-19 1 Oe. 1 1 P= 2 12 1 (2 √2 D-[64] of p=[171] -- [6 -4]
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5.3: Diagonalization Find the diagonal matrix D and invertible matrix P such that A- PDp-1 if possible. If it is not possibl which eigenspace(s) are to blame. e, eosplain A-1 2 1 3 -1 A 1 1 1 5 0 3 A- 0 2 0 し406
5.3: Diagonalization Find the diagonal matrix D and invertible matrix P such that A- PDp-1 if possible. If it is not possibl which eigenspace(s) are to blame. e, eosplain A-1 2 1 3...