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If this data is given how do I fill in the table
Beaker [FeSCN2+), M 1.60E-04...
if I have this given to me how do I find the concentration of FeSCN2+ at...
if I have this given to me how do I find the concentration of
FeSCN2+ at equilibrium?
| PARTI Beaker Absorbance 2 [FeSCN2t 160 X10 " + 9,08810-6 1.20x1074 + 6.81x10-6 8.00x10 - 4.548106 4,00 x 10-5 +2.27X10 0.618 – 6:11890-2 0.492 & 4.86810-2 8.346 £ 3.428102 0.157 † 1:55x10- 3 2. 4 Linear regression equation - Cusing yo mx+c) 0 = 0.6187 6:11X102= (3822.5)(1.60X10 44 908x104) +0.021 67 0.492+ 486X10 -2 = (3822.5)(1.20 x 104 + 681x106) +0.021 1...
How do I find the concentration of KSCN & FeSCN2+ from the following data? Solution Beaker...
How do I find the concentration of KSCN & FeSCN2+ from the following data? Solution Beaker 1 Beaker 2 Beaker 3 Beaker 4 Beaker 5 Volume of 0.200 M Fe(NO3)3. mL 2.5 mL 2.5 mL 2.5 mL 2.5 mL 2.5 mL Volume of 0.0020 M KSCN, mL .50 mL .75 mL 1.0 mL 1.25 mL 1.5 mL Volume of 0.50 M HNO3, mL 7 mL 6.75 mL 6.5 mL 6.25 mL 6 mL Total volume, mL 10 mL 10 mL...
if I have this given to me how do I find the concentration of
FeSCN2+ at equilibrium?
| PARTI Beaker Absorbance 2 [FeSCN2t 160 X10 " + 9,08810-6 1.20x1074 + 6.81x10-6 8.00x10 - 4.548106 4,00 x 10-5 +2.27X10 0.618 – 6:11890-2 0.492 & 4.86810-2 8.346 £ 3.428102 0.157 † 1:55x10- 3 2. 4 Linear regression equation - Cusing yo mx+c) 0 = 0.6187 6:11X102= (3822.5)(1.60X10 44 908x104) +0.021 67 0.492+ 486X10 -2 = (3822.5)(1.20 x 104 + 681x106) +0.021 1...
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