

1. Find R, for f(x) = 5x + 2 on the interval [1, 3). Round your answer to 6 decimal places. pr? +1 +8 dt 2. Use the Fundamental Theorem of Calculus to differentiate f(x 3. Evaluato: (a) [(x + Jar EVALUATE: (b) S** 3 cose do
BI U & A 5 5b. Factor the expression 5a. Factor the expression x' + 5x + 6 x² + 3x - 28 MUST SHOW WORK ON SEPARATE SHEET OF PAPER 2 6x - 14 = 0. 6. Solve for the exact values of x by completing the square: x Leave your answer in simplest radical form. MUST SHOW WORK ON SEPARATE SHEET OF PAPER 7 Chanc 2.2 A 2.unbate the followinn The My 2 4 3 5 6 9...
For the polynomial function f(x) = −5x(x + 2)2(x − 1)3:
For the polynomial function f(x) = -5x(x + 2)(x - 1)": 7. (4 points) The leading term when expanded is -5.2". Use this to describe the end be havior of f(x): as r → , f(x) → as I + -00, f(x) → 8. (4 points) Name the zeros of f(x) and each of their multiplicities. 9. (4 points) Come up with a rational function which has y =...
9 or 16 (9 complete) X 2.6.53 For f(x)=x +5 and g(x) = 5x +4, find the following functions. a. (fog)(x); b. (gof)(x); c. (fog)(2); d. (gof)(2) a. (fog)(x) = (Simplify your answer.) Enter your answer in the answer box and then click cha
If f(x) = 5x - 2 if - 53x32 , find: (a) f(0), (b) f(1), (c) f(2), and (d) f(6). x3 -2 if2<x56 (a) f(0) = (b) f(1) = 0 (c) f(2)= (d) f(6)=0
Problem #16: [2 marks] A solution, y = f(x), of the differential equation, x²y + 5x²y = xt has f(0) = }. What is f(1)? Problem #16: Enter your answer symbolically, as in these examples Save
4 - Let f(x) = 4 – 5x and g(x) = 2 4 be functions from R into R. Prove that f and g are inverse functions by demonstrating that fog=iR and go f = ir.
f(x) = 2x2 – 3, if x < 2 x2, if 2<x< 4 5x – 7, if x > 4 a) f(0) b) f(3)
Given, f(x) = {x #1, 2 5x<4 4,0<x< 2 (a) Sketch the graph of f(x) and its even half-range expansion. Then sketch THREE (3) full periods of the periodic function in the interval -12 < x < 12. (6 marks) (b) Determine the Fourier cosine coefficients of Ql(a). (10 marks)
is thisthe correct answer?
u = E[r* f(x)] = 1(1/16)+2(3/16)+3(5/16) +4(7/16) = 1/16+6/16+ 15/16 + 28/16 = 50/16 = 3.125 o2 = EC*(x-4)21 = 1(1 - 3.125)2 + 2(2-3.125)? + 3(3-3.125)+ 4(4 – 3.125)2 = 8.625 o=18.625 = 2.9368