using lens formula
1/f = 1/v - 1/u
1/9 = 1/ v + 1/11
v = 49.5 cm
magnification
m = - v/u = - 49.5 / 11
m = - 4.5
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Question 8 15 pts An object is placed 11 cm to the left of a converging...
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Problem 3: An object of height
2.8 cm is placed 26 cm in front of a diverging lens of focal length
16 cm. Behind the diverging lens, and 11 cm from it, there is a
converging lens of the same focal length.
a) Find the location of the final image, in centimeters beyond
the converging lens (such that a negative answer would indicate the
final image is on the same side of the converging lens as the
object).
b) What...