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AaBbCD A. AaBb C 5. Repeat step 4 for a lens with different property. The refractive index of the lens is 1.7 and radius of c
1 Object Distance (p) Image Distance (9) Magnification (m) Nature of the image (Real or Virtual/upright or inverted) 190 cm 1
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Answer #1

n = 1.7; r = 0.5 (unit is not given. so I take in m) .

from formula: 1/f = (n-1)*2/r

f = 0.357 m.

(a) s = 190 cm = 0.190 m

from lens formula: 1/f = 1/s + 1/s' (1)

image distance (s' )= - 0.40 m

magnification: m = -s'/s = 2.10 (2)

due to negative sign of image it will be virtual. since M is positive so it will be upright .

Note: Because unit of radius of curvature is not clear in question. so I am not solving other parts. You can calculate others parts from formula (1) and (2).

Nature of image can be determindes as: if s' is positive then real image and if negative then virtual image.

if m is positive then upright and if negative than inverted.

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