Question

Question 1 5 pts As shown in the figure, an unknown charge is located at the origin and an electron is located at x = +0.2 nm. If the net electric force on a small positive test charge is zero at x = -1.5 nm, what is the magnitude and sign of the unknown charge? test charge unknown charge Q electron 9 x=-1.5 nm x=0 X=+0.2 nm 0 -0.78e +0.78e 0 -0.018e +0.018e +28e

Answer 1

Ee q(+) @ - е x=-1.5mm x=0 2=0,2 nm Force q = 0 The e- will attract q (+), therefore Ee ( Electric field at x = -1.5m) due to the e- will be towards right. Now net force (given) Therefore EQ must towards left Lo q 1 be Ee le CS q Ee ) EQ 22. For that & must be tve is positive o

And from 2 Ee - Eq we get e utto [(0.2+1-5) 2104]? 1 () = UTE (1.5 x109) 2 >) e - 2 (0.2+15)? (1.5) 2 > o (1.5)? (0.2+(-3)? (1.5) ² x 1.6x10-19 (1.792 2 1.2457 x 10-19 = + 1.2457X10-19 e Q = +0.78 e option (6)