Question

A spring is hung vertically, and an object of mass m = 1 kg attached at lower end stretches the spring to position xı= 20 cm. When the mass increases to my =1.5 kg the spring stretches to new position x2 = 33 cm. What is the period of the spring-mass system when a mass of 2 kg attached to it? Hint, use x1, X2 , m,,mto find spring constant k and use the value of k to find the period of spring-mass system with mass = 2kg. (20 points)

Answer 1

Solution in the uploaded image

Solution Let unstrucked length - No 0 From figure, mig k(a,- no) Facecar | etrecereale n2 1 x d. 8 = ((0.20 - x0) - 6 For m2 K(2. no) meg 1.5x9.8= k(0.33-40) solving so 1.5= 0.33-xo 0.2 - No 0 2x1.5 – 1.500 = 0.33- no= -0.06m abour purting 37.69 N/m 1x 8.8 K= 0.20- (-0·06) For m- -21g. Time period, I = 21 T= 21 37.69 T= 1.45 sec 1) 37.69 # tit like if you understood the solution!!