Question

1. Mass "A" (1.2kg) sliding right at 6.0m/s collides head-on with mass "B" (2.8kg) sliding left at 1.8m/s, all on a horizontal frictionless surface. If the masses stick together and move off as one a) find the final velocity V of the stuck together pair b) find AEch of the collision in (a) On the other hand, if the masses collide elastically c) find V'A and V's after collision d) what is AEK? e) what is the impulse (magnitude and direction) on A from B in (c)?

Answer 1

An law per of conservation of momentum, miu,+ m2u2 (mit m₂) v va mu,+ m₂ 42 (mitm₂) 1.2 x 6+ 2.88-1.8 (1.2+2,5) 0.54 m/one ( b) 2 - 1 (m, 4m2) v²+ ( km, uit tmy ) =) DEH = -1/2 x (1.2+2-8) X 0.54 + ( 2x 1.2 x 6²7 2 x 2.8x1-82 A Elha 5.488 I LC) Viz topoma 2m2 ut mitha mitmz 1,2-2,8 x 6+ 2x2.8 x-1.8 z -4.92 m/ree 1-24 2.8 1-2 +2.8 2 m. midm. ", a mzom, mitha uz - Ugo 2% 1.2 X + 2.8-1.2 1.24.218 x-1,8 2 2.88 m/ree 1.2+28 At Hi 20 (Kinetic energy is conseved in elastic collision Impulse change in momentum. a m(of V:) - Impulse = 2.8 (2.88--1.8) = 13.104 kg m/re