Question

Given the triangle DeltaABC.WITH information A=1.344 b=4.8 and C=1.068 Find the semi perimeter of a triangle. Please can you put the answer in radians.

Given the triangle DeltaABC.with information A=0.427 a=9.0 and C=0.957.Find the semi perimeter of a triangle. Please put the answer in radians

Answer 1

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1.3 +4 + 1 ço 77° LA = 1.344 2C- .0c } 1.0687 1 5o 61.19 Given, b- 4.5 ZB= total angles nisich as is 180°. 180- 180- (Zat ac] [77° +61.19"] 41.57 = 41.81 XT 190 0.7297 aand <B using sin law sinB = Sin 61.19*4.8= 6.30 sine » c= Sin cxb. SinB Sin 41.81 using sin law, - = Sin 77 Sin 4 Sin B 7.01 => a = Sina xb Sin B a Sin 41.81 KB=0.7297 rad. Semi painetin at btc c= 6.30 a= 7:01 7.014 4.5+ 6.30 2 9.055 Senipuinch 9.055 9 2) 0.427 } Griven, 0.957 0.427 x 150/ 24.460 0.957 X 150 54.53 Augh risich a is IGO 180-(A +3] ICO- [24.46+ 54.83] = 150-[79.29] = 100.711 = 100.71 /160 = 1.7577 iad 3 sin law 21.35 using sin A sin B sinBea= Sin A Sin 100.71 Sin 24.46 b sin law, 17.76 using c=sine, a sin 54.83 x 9. sin 24.40 Sin a Sinc sinA atbtc B= 1.7577 ead Sanipaineta b = 21:35 9+ 21-35 +17.76 C-17. 76 2 24.05 24.05 danipaineta is