Question

please answer and explain!

Is it possible that you could see a higher-order color before you see all of the colors of the last order (for instance, a 4th order blue before a 3rd order red)? Explain your answer. HTML Editore B I J A A : I = = = = = = = = = - O 2N V D1 12pt Paragraph I O words

Answer 1

for grating by, m=0, 12, spectrum the position of the princepal maxima are given Idsino = my Where da la tb) - grating elemet is called Grating equation foro, geoth anden bienesbad marinade obterree central maxima will be of the same colour of Souce etselt for mto the angles of diffraction are different for different warelengths. Gee let us take grateng element is given to you 600 lines per inch, so find d = 2.54 = 4:X10-3cm Omb and Omr deberesents the angle of diffraction for mith order o spectrum coresponding to blue and red colour. sino = mildl for at de ander klece 04b = sin ll 4x4xlo 4x163 to 4x10-5cm] Oub = 2-29º. 6oo os 4x7x10-5 (for blece for 4th ander red 4x10-3 I for red color lux 7X15cm 048= sint sin- Oy=4.01° for god order red Osr = sint [3X3X) = 3:0 03 03r=3.0 since 03r7 04b so the 3rd order and 4th ander

thus forth ordrer soectra will overlap and the forth order spctrum for red color will not be observed for that particular grating element we had taken here as an example, it could be more then what we consider here.

so final conclusion we could see the higher order color spectrum, because of the angle coresponding to 4th order blue spectrum is less then 3rd order red color spectrum.