If f: A ⟶ B and g: B ⟶ C are functions . If g is onto, then g ∘ f : A ⟶ C is onto
Group of answer choices
True
False
Here g: B ⟶ C is onto i.e, every element in set C has at least one element as an image in set B
But this does not assure that every element in the set B will have at least one element as an image in the set A
And because of this, it is not sure that every element in the set C will have at least one element as an image in the set A
Therefore
If g is onto, then g ∘ f : A ⟶ C is not necessarily onto
Answer: False.
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Let f : A rightarrow D and g : B rightarrow C be functions. For each part, if the answer is yes, then prove it, otherwise give a counterexample. Suppose f is one-to-one (injective) and g is onto (surjective). Is go f one-to-one (injective)? Suppose f is one-to-one (injective) and g is onto (surjective). Is g f onto (surjective)? Suppose g is one-to one. Is g one-to-one? Suppose g f onto. Is g onto?
True or False: If f(x) and g(x) are two differentiable functions on an interval (a,b), and f(x)>g(x) on (a,b), then f'(x)>g'(x).
Answer Choices:
A) A, B
B) F, G
C) C, D, F, G
D) F
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