Question

A 10.00 mL sample of phosphoric acid is titrated with 20.15 mL of a 2.50 mol/L...

A 10.00 mL sample of phosphoric acid is titrated with 20.15 mL of a 2.50 mol/L sodium hydroxide solution.  

H3PO4 (aq) + NaOH ----> H2O (l) + Na3PO4 (aq)

a) Balance the molecular equation and write the net ionic equation.

b) calculate the molarity of phosphoric acid.

c) calculate the mass percent of phosphoric acid in the water mixture (density = 1.50 g/mL)

0 0
Add a comment Improve this question Transcribed image text
Request Professional Answer

Request Answer!

We need at least 10 more requests to produce the answer.

0 / 10 have requested this problem solution

The more requests, the faster the answer.

Request! (Login Required)


All students who have requested the answer will be notified once they are available.
Know the answer?
Add Answer to:
A 10.00 mL sample of phosphoric acid is titrated with 20.15 mL of a 2.50 mol/L...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Similar Homework Help Questions
  • A 10.00 mL sample of phosphoric acid is titrated with 20.15 mL of a 2.50 mol/L...

    A 10.00 mL sample of phosphoric acid is titrated with 20.15 mL of a 2.50 mol/L sodium hydroxide solution.   H3PO4 (aq) + NaOH ----> H2O (l) + Na3PO4 (aq) a) Balance the molecular equation and write the net ionic equation. b) calculate the molarity of phosphoric acid. c) calculate the mass percent of phosphoric acid in the water mixture (density = 1.50 g/mL)

  • A 10.00 mL sample of phosphoric acid is titrated with 20.15 mL of a 2.50 mol/L...

    A 10.00 mL sample of phosphoric acid is titrated with 20.15 mL of a 2.50 mol/L sodium hydroxide solution. H3PO4 (aq) + NaOH --> H2O (1) + Na3PO4 (aq) a) Balance the molecular equation and write the net ionic equation. b) calculate the molarity of phosphoric acid. c) calculate the mass percent of phosphoric acid in the water mixture (density = 1.50 g/mL)

  • A 15 ml aliquot of 1.00 M phosphoric acid is titrated with sodium hydroxide using phenolphthalein...

    A 15 ml aliquot of 1.00 M phosphoric acid is titrated with sodium hydroxide using phenolphthalein as an indicator. If it takes 20.00 ml of sodium hydroxide to reach the endpoint, what is the molarity of the sodium hydroxide? Answer with appropriate significant digits. H3PO4 (aq) + NaOH (aq) --> H2O (l) + Na3PO4

  • what is the molarity of a solution of a phosphoric acid that is made by dissolving...

    what is the molarity of a solution of a phosphoric acid that is made by dissolving 8.00 g of H3PO4 on 0.1 L of water. A.) 0.0816M B.) 0.816 M C.) 0.1 M D.) 1.6 M Write the correct molecular equation, complete ionic equation, and net ionic equation, for the reaction that occurs between cobalt(II)chloride and sodium hydroxide

  • An aqueous solution of 0.100 M phosphoric acid (12.0 mL) is titrated with 0.400 M KOH...

    An aqueous solution of 0.100 M phosphoric acid (12.0 mL) is titrated with 0.400 M KOH as shown below. phosphoric acid has three pKas: 2.148, 7.198, 12.375. H3PO4(aq) + OH-(aq) H2PO4-(aq) + H2O(l) H2PO4-(aq) + OH-(aq) HPO42-(aq) + H2O(l) HPO42-(aq) + OH-(aq) PO43-(aq) + H2O(l) Calculate the pH of phosphoric acid solution before any KOH has been added. We were unable to transcribe this imageWe were unable to transcribe this imageWe were unable to transcribe this image

  • Homework Acids and Bases Name: 1) Write in the products for this acid-base neutralization reaction, then...

    Homework Acids and Bases Name: 1) Write in the products for this acid-base neutralization reaction, then balance the equation. HBr(aq) + Ca(OH)2(aq) → 2) A 8.00-ml sample of an H.PO, solution of unknown concentration is titrated with a 0.2090 M NaOH solution. A volume of 6.12 mL of the NaOH solution was required to reach the equivalence point. What is the concentration of the unknown H3PO4 solution? 3 NaOH + H3PO4 → Na3PO4 + 3 H20 3) What volume in...

  • 10.00 mL Nitric acid was titrated with NaOH of 0.100 molarity until the equivalence was reached. 15.2 mL of NaOH were re...

    10.00 mL Nitric acid was titrated with NaOH of 0.100 molarity until the equivalence was reached. 15.2 mL of NaOH were required. Find: A) Concentration of nitric acid before titration B) pH of solution before titration C) pH of solution after 15.1 mL of sodium hydroxide is added D) pH of solution after 15.3 mL of sodium hydroxide is added

  • urgent!!! The neutralization reaction between ammonium hydroxide (NH4OH, MM = 35.04 g/mol) and phosphoric acid (H3PO4,...

    urgent!!! The neutralization reaction between ammonium hydroxide (NH4OH, MM = 35.04 g/mol) and phosphoric acid (H3PO4, MM = 98.00 g/mol) proceeds according to the following balanced eqation: 3NH4OH(aq) + H3PO4(aq) ->3H20(1) + (NH4)3PO4(aq) What is the final molarity of the ammonium ion (NH4+, MM = 18.05 g/mol) when 25.0 mL of 1.20 molar ammonium hydroxide is reacted with 25.0 mL of 2.00 molar phosphoric acid?

  • a 100 ml solution of 0.250 M formic acid (HCOOH) was titrated to its equivalence point...

    a 100 ml solution of 0.250 M formic acid (HCOOH) was titrated to its equivalence point with 50 mL of sodium hydroxide. The complete molecular equation for the reaction is shown below HCOOH (aq) + NaOH (aq)---------> HCOONa (aq) +H20 (l) Ka of HCOOH= 1.7 x 10 ^-4 calculate the pH at the equivalence point

  • 18. (5 pts.) A 155.0 mL portion of aqueous phosphoric acid solution was completely neutralized by...

    18. (5 pts.) A 155.0 mL portion of aqueous phosphoric acid solution was completely neutralized by 45.38 grams of Lithium hydroxide. The chemical equation is: 3 LiOH (s) + H3PO4 (aq) → Li3PO4 (s) + 3 H2O (1) The concentration of the phosphoric acid, in molarity, is: (a) 4.075 M (b) 1.611 M (c) 11.40 M (d) 3.942 M

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT