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At a Chinese restaurant, dinner for 8 people consists of 3 items from column A, 4...

At a Chinese restaurant, dinner for 8 people consists of 3 items from column A, 4 items from column B and 3 items from column C. If columns A, B and C have 5, 7 and 6 items respectively how many different dinner combinations are possible?

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Answer #1

Doubt or problrm in this then comment below.. i will explain you..

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please thumbs up for this solution..thanks..

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different dinner combinations = 5C3 * 7C4 * 6C3 = 7000

answer = 7000 different combination possible

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