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x = t^2 - 2t + 4, y = t^3 - 6t^2
8. a) Set up the integral you would need to evaluate to find the length of the curve given in #3 if Osts 10. b) Set up the in
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so/? Given X t?- 3044 , 3 y = t²_6tt. So da at 9t-2. dy de 84? 12+ ? length of love AP ſ dx + (dy je at S ) (@+ 2jf +(387–Hence, length af curve slºj q¢4> 72 974-72 +3 +1484²-8t tu dtGiven curve Us u Siin 30. (b) Qa66830 so do d 4.3 cosao = 11 length of curve si ga tidak do (do 71/3 = 3 x 22+(12.60330% do 3Hence aro length= 1 ? 14 8 cos?30 dol

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