Question

5. Chris claims that the average weight of tears shed by each student after an exam is more than 30 grams. You ask 42 random
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Ans 5)

Null Hypothesis states that the average weight of tears shed by each student after an is:

H_{o}:\mu = 30

Alternate Hypothesis states that the average weight of tears shed by each student after an is more than:

H_{a}:\mu > 30

Sample size n = 42

Sample mean \bar{x} = 30.3

Population\: standard\: deviation\: \sigma = 1

Significance level \alpha = 0.1

Since the population standard deviation is known we will do z-test

Test statistics:

z = \frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}

= \frac{30.3-30}{\frac{1}{\sqrt{42}}}

=1.94

Test statistics z = 1.94

Based on rejection region: The critical value for rejection region is z_{1-0.1} = 1.282

Since, z > zc (Reject Null Hypothesis.)

Based on P-value: P-value is 0.0262 Since, P-value < \alpha (Reject Null Hypothesis.)

Conclusion: Yes, there is enough evidence to conclude that the average weight of tears shed by each student after an is more than 30 grams.

Add a comment
Know the answer?
Add Answer to:
5. Chris claims that the average weight of tears shed by each student after an exam...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Chris claims that the average weight of tears shed by each student after an quiz is...

    Chris claims that the average weight of tears shed by each student after an quiz is more than 30 grams. You ask 42 random students if you could collect their tears after an quiz and find that the average weight was 30.3 grams. Assume the population standard deviation is 1 gram. At α = 0.1 is there enough evidence to support Chris’ claim?

  • At a=0. is there enough evidence to support 6. A researcher claims that the proportion of...

    At a=0. is there enough evidence to support 6. A researcher claims that the proportion of males who have tested positive for Covid-19 is less than the proportion of females that have tested positive for Covid-19. In a random sample of 500 males, 4% of them tested positive. In a random sample of 500 females, 4.3% of them tested positive. At a = 0.01, is there enough evidence to support the researcher's claim?

  • Winter 2018 AT 103 Test II Chapters 6-11 a( \ 1. The average number of miles that 90 truckers drove in a day was 540 with a standard what is the 99% confidence interval of the true mean number of...

    Winter 2018 AT 103 Test II Chapters 6-11 a( \ 1. The average number of miles that 90 truckers drove in a day was 540 with a standard what is the 99% confidence interval of the true mean number of deviation of 40 miles, miles driven by all truckers? Dr. Christina Cuttleman, a nutritionist, claims that the average number ofcalories in a serving of popcorn is 75 with a standard deviation of 7. A sample of 50 servings of popcorn...

  • 1. You measure 42 textbooks' weights, and find they have a mean weight of 47 ounces....

    1. You measure 42 textbooks' weights, and find they have a mean weight of 47 ounces. Assume the population standard deviation is 3.5 ounces. Based on this, construct a 90% confidence interval for the true population mean textbook weight. Give your answers as decimals, to two places 2.If n=16, ¯xx¯(x-bar)=43, and s=13, construct a confidence interval at a 99% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place. 3.SAT scores are...

  • STA2221 examples on CI & Testing of Hypothesis Name MULTIPLE CHOICE. Choose the one alternative that...

    STA2221 examples on CI & Testing of Hypothesis Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answer the question Provide an appropriate response. 1) Find the critical value,te for 0.99 and n-10. A) 3.250 B) 3.169 1.833 D) 2.262 2) Find the critical value to forc=0.95 and n=16. A) 2.947 B) 2.602 2120 D) 2.131 3) Find the value of E, the margin of error, for A) 1.69 B) 0.42 0.99, n=16 and s=2.6. C)...

  • Using the book, write another paragraph or two: write 170 words: Q: Compare the assumptions of...

    Using the book, write another paragraph or two: write 170 words: Q: Compare the assumptions of physician-centered and collaborative communication. How is the caregiver’s role different in each model? How is the patient’s role different? Answer: Physical-centered communication involves the specialists taking control of the conversation. They decide on the topics of discussion and when to end the process. The patient responds to the issues raised by the caregiver and acts accordingly. On the other hand, Collaborative communication involves a...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT