Question

5.00 in 5. Arm AB has a constant angular velocity of 2 rad/s clockwise, determine: a) the velocity of point B b) the angular velocity of bar BC c) the angular velocity of bar CD c) the velocity of the point C d) the acceleration of point B e) the angular acceleration of bar BC f) the angular acceleration of bar CD. (40) D o 8.00 in 60° B 3.00 in

Answer 1

sis Date..... Sell 450 sin 45° 8 in B WAB Bin A) 300 WAR Angular velocity of AB, - 2 Rad/sec (clockwise) from the figure losition of B with respect to A 13 los 300+ 3 Sin 30° 2.5980 i + a P 1.5 B. Vo WARX [TELA so, velocity of B, -2k x [2.5980 **+5.5;] Jo -5. 1563 + + 3 3 Ivalo (5.136)² +O)? Velocity of B B, vel 5.999 in/sec

Position of C with respect to R Melbe 8 inches Position of C with respect to D. Melo ( 5 6054508 + 5 sin454 ricco (3.5355 1 + 3,5355 o 3557) Ve Sin 45 2 -0.70711 Ve Jo + x algo, Velocity of C, Je Ve Cosuso 45 7 0.7071 Vej 0.70 71 V2 - 0.7071've So, velocity of e, vere Te & Wars X Mie -0.7071 Vio 1- 0.7071 ve 2 = 3 - 5.1365 + weer i Compairing and ŷ Components i Comparents : -0.7071 We = 3 -8 wasio Ý Components : Nc² 7.3483 in sec Velo city of poict C, ve = 7,3483 insec 1 0.7071 Vc = - s.1gbo

Date... becomes Equation i - 0.7071 Vc 3-8WBC - 0.7071 (7.3483) = 3-8 Woc. Wec = 1.024 vad/sec b) Angular Velacity of BC, War = 1.024 and/ see (ANTI-CLOCKwise) Angular velocity of Bar Co Wo CD Wce 7-3483 5 1.4696 rad see Acceleration of point B dez LAB X JINA - (WAR ) ² (STRIA) (WAS)? (SIELA) Since, Bar AB has - (2)? (2.5980 1 +1:55] 10.392 i-67) in AnrqULAR VELOCITY Z - -CONSTANTA 3 BO a so hal J (10.392)² + (6) 2 11.99 in seca So, acceleration of point Bus 11.99 in[sec?