Question

For each section below with the given shear force, plot the shear stress using VQ/It. Show the location(s) of the maximum stress.

V = 12 k 5 in 12 in 5 in 5 in 2 in 5 in

Answer 1

Solue V=121. 5 inch 6 inch Ilinch Trak. Tedin 7.2 inch linch 199.16 5 inch 2 inch 5inch 5 inch. T NAT I b = Z 12000 x AxT Terb (6x2) + (1x 10) = 12 + 10 = 22 (inch) (A x y ) + It A292 (A1 + A2) p' = (640x3) + (1x10x5.5) 12 +10 T' 36 +55 - 4.136 inch from top. T = 1.864 inch frome bottome. + A.92 & 62 d3 A243 + 22 bid3 Ixx bą dot + +4393 12 12 12

LC 6 inch from top I was = m 129+(3400) + 5123+ (1040) + 5y9210 228 + 3.33 + 3.33 = 294.6674 inch)" 12 12 inch. WÁT I b 12000 x 22 x 1.864 094.667 12 Tuan 139.167 ob kinch)? (at neutral anie) Ve 15 K. trinch 16 12 in 2 inch -331.03 248.27 9.085 Inch I inch x k3 inch 544.60 557.34 2o (3 Binches. 8 inch. y = A.4, + A2 42 + A3 43 (A, & A2 + A₂) (4x2x1)+(773x5.5) + (833x10.5) (8 +21+24) 9 = 7.085 inch Le

bid? Ag? t body of A3 7 2 + bados + Aay? 3 Tyy 12 12 12 Txx 111023 +(8 »(7.085–119) + 372 3+(31»(7.085-5,5) + 8x033 +(24 %(10.5-7.085)?) 12 12 Ixy = 2.667 + 296.211 + 85.75 + 52.75+ 184179.9 Ixx 735.29 (inchga A' 11 y All (402) + (5.08523) 23.255 (inch)? A2 TA' Ar y = 15.08523x2.542)+(1152 it. Az *6.085) (5.085-8) + (420 3.76 inch A 7 - VAY = ТЫ 15000 x 28.255x3.76 735.27 x 3 694.60 lb | Cinchy? (at neutral anis) T =

V doo K 1 1227.27 5inch 409.09 110636 do inch Joimh 2 5inch Sinth 20 inch 1227.27 109.09 5inch Boinch Y 20 do inch (as Section is Symmestriel) Ixx 30% 203 20x103 12 12 Ixy = 20000 2666.67 18333.33 (inch) A' = (5030) + (525) +(505) A' = 150 + 25 + 25 = 200 Cinch) ² AY, & A2Y 2t A3Y Art A2t Az Ti = (5x5x2.5) + (505x2.5)+(5330275) (25+25+150 Ý ! 6.25 inch t VÁY 16 200x103 x2000 6.25 18939.33110 tmar 1363.63 lb /Cinch) 2 ( at nourhral axis)