We know the effect of applied force on a rotational body acts like torque on that body.
And the torque causes the rotation. Troque T = r×F
Where r = distance of point of applied force and the center of rotation. Since for top puck the r has greater value so the torque will have also greater value.
Since rotational acceleration is directly proportional to the torque applied on the body. After5 seconds The top puck has a greater angular speed.
Strings are wound around two pucks identical in size. One string is around the pucks outer...
Problem 1 Two identical pucks, each of inertia m, are connected to a rod of length 2r and negligible inertia that is pivoted about its center (that is, there is some sort of pin though its center, around which it can rotate without friction). A third puck of inertia m/2 strikes one of the connected pucks perpendicular to the rod with a speed vi. Assume the collision is elastic. (a) Draw a diagram of the situation, clearly labeling the direction...
A bicycle wheel is mounted on a fixed, frictionless axle, with alight string wound around its rim. The wheel has moment of inertia I=kmr2, where m is its mass, r is its radius, and k is a dimensionless constant between zero and one. The wheel is rotating counterclockwise with angular velocity w0, when at time t=0 someone starts pulling the string with a force of magnitude F. Assume that the string does not slip on the wheel.Part ASuppose that after a certain time tL,...
hello, im kind of new to double slit diffration stuff. please
help! thank you!
3. Laser light of wavelength 2 is incident on a mask containing two very narrow slits. A screen is placed beyond the mask. The photograph shows the pattem of bright spots (shown in white) and dark spots (shown in black) that appears near the center of the screen. Point D in the center is the brightest. (a) If the wavelength of the light is decreased, would...
Physics 120 Worksheet 9- Moment of Inertia and Statics Problem 4. Analyzing Torque- You take the wheel from Problem 3 and drill a tiny hole through the center of the x so you carn mount the wheel in an axle. Now you tie three different pieces of string to the wheel and apply the three tension forces of IN to the wheel. Fri is applied to the top of the wheel and points left. Frz is applied to the bottom...