Question

Suppose the angular velocity of a disk of radius R = 6 cm increases uniformly from 14 rad/s to 24 rad/s in 0.04 s. What is the magnitude of the TOTAL acceleration of a point on rim of the disk when the angular velocity is 24 rad/s? O 0.18 m/s2 0 38 m/s2 O 0.15 m/s2 O 35 m/s2 200 m/s2 O 50 m/s2 O 0.72 m/s2 o 15 m/s2 O 3 m/s2

Answer 1

Time period is independent of mass.Hence ,time period will remains same.

Total acceleration: az ti Translational var}+(ak)? Rotational Quy=aXR = do at XR- 24-14) x 6610-²= (29.00) 0.04 ap = w?R= (24) ² x 6x10 -2 = 34.56 To rade ac, s vels) + 84.51)2 = 3225+1197.3936 11419.3936 = 37.67 m/s² Hence, Total acceleration is a = 37.67 ~ 38 mis a 2 time period is given by : = 21 NA It is independent of to mass 99 Therefore, time period will remains same after doubling the mass too. Therefore, correct option is 't