Question

Find all solutions to the triangle described below. A = 63º, b = 7.5 yd. a = 6.8 yd Apply the rules regarding the use of significant digits to each angle and length after all computations are complete. O a. B = 39º. C = 78°, c = 2.4 yd b. B = 79°, C = 38°, c = 4.7 yd or B' = 101°, C' = 16°, c' = 2.1 yd c. B = 799, .C = 38°, c = 4.7 yd d. B = 79°, C = 38°, c = 4.7 yd or B' = 101°, C' = 78°, c' = 2.4 yd e. no solution O OO

Answer 1

solution:- Given A = 60 b= 7.5 yd a= 6.8 yd find all the possible cases: we use sine law to CA b C sinn SinB sinc a b 11 sin A Sin B sinA = sin B b. sina sin B a b T B - sint ( busin A.) sin" ( 7-5 sinc3) L B 0 1 79. 3355 LB 79° . As we know LA+LBtLc = 180° LC= 180°-LA-LB = 180-63-79° ㅕ 0 Cc 38 Again using sin law. a since SINA sing a .sinc - 6-8 sin 63 sin 38 = 4.6986 sina

T 4.7 yd 'first possible solution is 790, C = 38", C:= 4.7 yd B - NOW we know that sin (180 - 0 ) = sino sin ( 180 -79) = sin rol B'a 1010 o As we know LA + CB1+2C! = 180 Lola 1800-LA-LB' = 1800-630-1010 Icel= 16 cl Again using sine law sinci sinc a SINA = ا SIO A - اع 6.8 sin 16 2.10 36 sin 63 - ام 2.1 second possible solution is B!= 1010 ,115160, c'= 2.1 yd Answer :- option b)