Question

A potter's wheel, with rotational inertia 21 kg.m2, is spinning freely at 40 rpm. The potter drops a lump of clay onto the wheel, where it sticks a distance 1.2 m from the rotational axis. If the subsequent angular speed of the wheel and clay is 32 rpm what is the mass of the clay? 3.1 kg 4.3 kg 2.4 kg 4.0 kg 3.6 kg

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Answer 1

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sec 1) I = 21 kg-m², Wy=forpu = 40X 27 rad 8=1.2m, wf = 324 pm, m=? Using Conservation of angular momentum aboutatis, I wi = I wf + mwenye => 21(40-32) x 25 (373) 21:22 = m = 1 3.6458 kg option (E) is true. こ mx 8. = 0.5 = 3 x= A cop (wt+d) W = 27 = 21 at to, x=2cm, > 2=4 Cop (27 x + 2) copo = A :.x=4cm) Cop ( 21 t +T2) Aul option, (c) is correct 3) A A=3.5cm, max = 29 con/sec, x=1.75cm V=W JA222 2 V = (3.5) 5(7,5) 2- (175)2 (Vmax=AW) v=25.11 Coufsec Joption (d). is correct 4) if R. B to means A and B are I to each other 1 AXB)= AB singå= AB option (a) is Correct And