Question

a. show Uz = 0

b. Show (SIGMA)z2 = 1

Suppose the random variable Y has a mean of 15 and a variance of 36. Let Z = 1 -(Y – 15). V36 Show that uz = 0. Hz=EO (Y-D] =

0 0
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Answer #1

2 given ely -15 and by = 36 i let Z = TIS CY-15) a) The mean of z is given by Wz - El Tar (4-15)] ECY-15) E(Y)-15 136 136 E((

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