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1. Let f (x) = -x^3 - cos x With po = -2 and p1 O, find p2 using the Secant method. * (1 Point) Let f(x) = – x3 – cos x. With
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then P2 = fo) -x3-Cosa f(po) = -(-2) 3_ Cos(+2) a 8.416 f (P= -(0)3 (0)3 – Cosco) -) Pof (6) - PF(Po) fle) - fll) P [t2)(-1)

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