please help. I have included Appendix E. I do not know
what to look for in it. Thank you


We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
please help. I have included Appendix E. I do not know what to look for in...
Using data found in Appendix E of your textbook calculate the
nonstandard emf for each of the following reactions if the
concentration of each of the ions in these reactions is 0.0005
molar and everything else is standard (use 298 K for the
temperature, R = 8.314 J/mol-K, and F = 96,485 C/mol):
Using data found in Appendix E of your textbook calculate the nonstandard emf for each of the following reactions if the concentration of each of the ions...
2. Using the decay chain for 238U, calculate the amount of time it takes 5.0 kg of 238U to decay to 2.5 kg. What mass of 206Pb is produced? (5 points) (V) Helpful Stuff Thermodynamics: AG° = AH-TAS Nernst Equation: 6 = 6 - (RT/nF)InQ AG=RTIK At 25°C: 8 = 6 - (0.0591/n)logQ ΔGIRT Ke=e AGⓇ = -nF8° Units/Constants: Volt: 1 V=1/C Faraday: 1 F -96,485 C/mol e Arrhenius Equation: k = Ae Ea/RT R= 8.314 J/mol K Integrated Rate...
5. How much faster would a reaction be if a catalyst is used that lowers the activation energy from 20.0 kJ/mol to 10.0 kJ/mol? Do the calculation at two temperatures: first at 25.0°C and then at 0.0°C. (20 points) (V) Helpful Stuff Thermodynamics: AG° = AH-TAS Nernst Equation: 6 = 6 - (RT/nF)InQ AG=RTIK At 25°C: 8 = 6 - (0.0591/n)logQ AGRT Ke=e AGⓇ =-nF8° Units/Constants: Volt: 1 V = 1 J/C Faraday: 1 F = 96,485 C/mole Arrhenius Equation:...
1. How do I read the half reaction table?
2. If im asked for the best reducing agent from Cu+, Ag+, F2, and
Fe3+, where do I look first in the table? before the arrow or after
the arrow?
3. Sometimes a value that has originally a positive (V) from the
table it will have the negative sign in a homework problem, and
viceversa, so the question is, how do I use the positive and
negative signs in respect to...
help!!
(CH3),CBr + 1 → (CH3),CI + Br the following data were collected: [(CH3)3Br] (M) Time (s) 0.600 0 0.424 10.0 0.300 20.0 0.212 30.0 0.150 40.0 Determine the rate law for this reaction and calculate the rate constant. (20 points) E (V) Thermodynamics: AGº - AH-TAS Nernst Equation: 8 = 8°-(RT/nF)InQ AGⓇ--RTINK At 25°C: 8-6° -0.0591/n)logQ AG RT K-e AG° = -nF8° Units/Constants: Volt: 1 V-1 JC Faraday: 1 F -96,485 C/mole Ea/RT Arrhenius Equation: k = Ae R-8.314...
Consider the following species. Cut Ce3+ Ag+ Zn2+ What is the standard potential for the reaction of Cut with Zn2+ to produce Cu2+ and Zn? E = 0.28 X v Will Cut be able to reduce Zn2+ to Zn? no (yes or no) What is the standard potential for the reaction of Ce3+ with Ag! to produce Ag? Ex= 0.90 x v Will Cell be able to reduce Ag! to Ag? yes (yer or no) Ered (V) 0.68 0.52 0.40...
7. Using the following reaction progress diagram, answer the questions below: wiring Energy A G Rxn. a. How many steps are in the reaction? How do you know? (4 points) b. Which letter corresponds to the rate-determining-step? Explain your choice. (6 points) c. Is the reaction exothermic or endothermic? How do you know? (4 points) d. If the energy at point B is lowered, what will happen to the rate of the reaction will it increase, decrease, or stay the...
Fill in the Blanks 0.34 Half Reaction E. (V) Half Reaction Erd® (V) F + 2e →2F 0+ 2H + 2e →H,02 0.68 Ag* + e → Ag Cu* + e → Cu 0.52 Co? + e Co? O2 + 2H,0 + 4e → 40H 0.40 H,O, + 2H + 2e → 2H,0 Cu2+ + 2e → Cu Cet+e → Ces Cu2+ + e → Cut 0.16 PbO, + 4H+ +50,2 +2e → PbSO, + 2H,0 2H* + 2e →...
2.87 Ered® (V) 0.68 0.52 0.40 0.34 0.16 Half Reaction F,+ 2e →2F Ag* + e → Ag Co3 + e + CO2- H2O2 + 2H+ + 2e → 2H,0 Ce4+ + e → Ce+ PbO, + 4H+ + SO42- + 2e → PbSO, + 2H,0 Mno, + 4H+ + 3e → MnO2 + 2H,0 2e + 2H+ + 10, → 103 + H2O Mn0, +8H+ + 5e → Mn2+ + 4H,0 Aul+ + 3e → Au Cl2 + 2e...
1. Which metal can reduce Ni2+ ions but not Fe2+ ions?
Cd²⁺,Cr,Sn²⁺,Sn,Cd
2.Which species can oxidize Sn but not Fe?
Ni,Ni²⁺,Pb²⁺,Cd,Pb
1.68 1.51 1.50 1.09 1.00 0.96 0.95 FAO) + 2 H,0,1a) + 2H(aq) + 2e PO4 + 4H"(aq) + S0,00) + 2€ Mno. (aq) + 4H(aq) + 3e Mno,aq) + 8H(aq) + 5e Au?+ (aq) + 3€ PbO (8) + 4H(aq) + 2 Cl@) + 2 Cr,0,?" (aq) + 14 H*(aq) + 6e 0,(@) + 4H(aq) + 4e MnO...