Question

6. Oil (sp gr 0.90) is discharging through a 4-in. circular sharp-edged orifice in the end of a 6-in. pipe. The pressure head on the center line of the pipe just upstream from the orifice is 30 ft of oil, and discharge takes place into a closed tank in which the vapor pressure is – 3.0 lb per sq in. The discharge is not submerged. The orifice coefficients for this condition are: C = 0.68; C, = 0.97. Compute the discharge. 7. A calibration test of donifico in the

Answer 1

head in closed tank =-3lblinchr. (blin Soil 3 in terms of height of oil -3. Yo Lint 0.0325203 U/int = - 92.25 inches of oil = -12.25 x I ft ofoil 12 = -7.6875 ft of oil. "Total head available for orifice Head before - Head after orifice orifice = 30- (-7-6815) = 37.6875ft of oil oto oil. = 37.6875x (0.3048m) tl. 48715.m. of oil h= 11-48715 m Now Q = cc. a. cv /29 h where; c= 0.68, (r=0.97 a= ut in

> a= 4T* (39.87 (22.2. mga 3 8.10735x10 mr. and , g=9081 ml seev. - Q = 0.68x8.10735x163x0.97 2x9.84 X11.4875 3 80.28145 X10 lec Q = 0.08028145 mec "Answer Q= 0·08028145.x 6.28084133 sec Q = 2.8350092 ft² sec {imeter & Answer =3.2808 ft ? to consider; in which ever units you want.