24)
| Applying chi square test of independence: |
| Expected | Ei=row total*column total/grand total | facts | Cover-up | Total | |
| dem | 56.2874 | 294.7126 | 351 | ||
| rep | 49.7126 | 260.2874 | 310 | ||
| total | 106 | 555 | 661 | ||
| chi square χ2 | =(Oi-Ei)2/Ei | facts | Cover-up | Total | |
| dem | 3.627 | 0.693 | 4.3192 | ||
| rep | 4.106 | 0.784 | 4.8905 | ||
| total | 7.7328 | 1.4769 | 9.2097 | ||
| test statistic X2= | 9.21 | ||||
| p value = | 0.0024 | from excel: chidist(9.2097,1) |
since p value <0.05

25)
for this data table of observed frequencies are required.
facts cover-up 309 dem 42 rep 64 246 In a Fox news poll asking samples of...